Guest ThePhilosopher Posted June 20, 2010 Report Share Posted June 20, 2010 I am studying for exam P and I'm on problem 39 of 149 in a free packet I received, but I'm worried that simply solving problems isn't going to be enough. If anyone has sat for or us studying for exam P I'd like to hear your study recommendations. Quote Link to comment Share on other sites More sharing options...
Guest ThePhilosopher Posted June 21, 2010 Report Share Posted June 21, 2010 Maybe something more concrete, anyone? I'm stuck on setting up the integral here from here - I'm not utterly familiar with this type of problem. Quote Link to comment Share on other sites More sharing options...
Member X Posted June 21, 2010 Report Share Posted June 21, 2010 I really should have paid more attention in maths at school... I'm no help whatsoever, sorry!! Quote Link to comment Share on other sites More sharing options...
Guest ThePhilosopher Posted June 21, 2010 Report Share Posted June 21, 2010 (edited) No worries, I figured it out (had to look up a thing or two): Edited June 21, 2010 by ThePhilosopher Quote Link to comment Share on other sites More sharing options...
Member X Posted June 21, 2010 Report Share Posted June 21, 2010 My head hurts just looking at that! Quote Link to comment Share on other sites More sharing options...
Guest ThePhilosopher Posted June 22, 2010 Report Share Posted June 22, 2010 I'm stuck with this summation - I'm not allowed to use a graphing calculator at all. Quote Link to comment Share on other sites More sharing options...
Member X Posted June 22, 2010 Report Share Posted June 22, 2010 Nope, I'm still no use to you... LoL Quote Link to comment Share on other sites More sharing options...
StormTooper4 Posted June 22, 2010 Report Share Posted June 22, 2010 Good grief, I used to be able to do that stuff. Hence why those actuary boys get paid the big bucks. Good luck with that lot. Be keen to hear how you go. Quote Link to comment Share on other sites More sharing options...
cougaree Posted June 23, 2010 Report Share Posted June 23, 2010 I forwarded to my bother in law and this is his reply. "I am pretty sure I solved it. The answer is D. first find the distribution of X. X = { 0 if x < 0 1-e^(-2/3) if x = 2 1/3 * e^(-x/3) if x > 2 Then just compute E(x). E(x)= integrate(x*0,x,-infinity,2) + 2*(1-e^(-2/3)) + integrate(x/3 * e^(-x/3),x,2,infinity) which equals 2+3e^(-2/3) I got "1-e^(-2/3)" by using the CDF of T solved at x=2. This will give me the probability that the device failed during the first two years. let me know if I got the right answer. It was fun working on it." What do you think? Did he get it right? Quote Link to comment Share on other sites More sharing options...
plaifender Posted June 23, 2010 Report Share Posted June 23, 2010 soooo not cool. Why did you just do that to me!? Quote Link to comment Share on other sites More sharing options...
cougaree Posted June 23, 2010 Report Share Posted June 23, 2010 huh? Quote Link to comment Share on other sites More sharing options...
Guest ThePhilosopher Posted June 23, 2010 Report Share Posted June 23, 2010 I forwarded to my bother in law and this is his reply. "I am pretty sure I solved it. The answer is D. first find the distribution of X. X = { 0 if x < 0 1-e^(-2/3) if x = 2 1/3 * e^(-x/3) if x > 2 Then just compute E(x). E(x)= integrate(x*0,x,-infinity,2) + 2*(1-e^(-2/3)) + integrate(x/3 * e^(-x/3),x,2,infinity) which equals 2+3e^(-2/3) I got "1-e^(-2/3)" by using the CDF of T solved at x=2. This will give me the probability that the device failed during the first two years. let me know if I got the right answer. It was fun working on it." What do you think? Did he get it right? No - nowhere is the Poisson distribution nor the payment. You cannot integrate because the Poisson distribution is discrete and line segments have 0 area. I've got it figured out finally though. Quote Link to comment Share on other sites More sharing options...
Brightight Posted June 24, 2010 Report Share Posted June 24, 2010 Surely if you're going to exponentially distribute with a mean of three years you're going to need a gen? A rep wouldn't last that long under normal conditions. I suggest you try a gen forum :D Quote Link to comment Share on other sites More sharing options...
federico.fiorillo Posted June 24, 2010 Report Share Posted June 24, 2010 I really should have paid more attention in maths at school... I'm no help whatsoever, sorry!! me too :shock: Quote Link to comment Share on other sites More sharing options...
mas6002mi Posted June 24, 2010 Report Share Posted June 24, 2010 'poisson distribution' Quote Link to comment Share on other sites More sharing options...
nikki6 Posted June 24, 2010 Report Share Posted June 24, 2010 WOW, I think that just destroyed my JAWS software!! lol. Cougaree and his brother were right on their answer, the answer was for the first problem not the second. Sixx Quote Link to comment Share on other sites More sharing options...
Guest ThePhilosopher Posted June 26, 2010 Report Share Posted June 26, 2010 I see that now Sixx, I was confused as I had answered the first already - I feel doltish. Quote Link to comment Share on other sites More sharing options...
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