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Devedander

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Cheaters :o

BTW Ken unless they do things different down under, I don't think you meant to say vertical...

Here's another one:

3 Guys are on a tirp and need a room at a hotel, they ask how much and are told $30 a night. So they each pony up $10 and go to the room.

A few minutes later the frontdeskman realizes it's only $25 a night and sends the bellhop with $5 change to the mens room.

Upon arrival the men thank the bellhop but can't split $5 between 3 people so they each take $1 and give the bellhop a $2 tip.

So since each paid $10 but got back $1 they each spent $9.

$9 * 3 people is $27.

They tipped the bellboy $2.

$27 + $2 is $29

Where is the last $1?

Edited by Devedander
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Pug you party pooper!! Dun be a pug! ;)

4 soldiers are captured by the enemy and told they will be given a chance to be let free. The captors have 2 black hats and 2 white hats. The men will be blindfolded and a hat placed on each mans head, then 3 will be lead into one room and 1 into another. The 3 in one room will be lined up facing a wall such that each man can see the hats of the men in front of him, but not his own - crude illustration:

ROOM 1 ROOM 2

| O> | | <O <O <O |

The < represent the guys nose so you can see which way he is facing when lined up. The guy by himself can see nobodys hat and the other guys can only see the hats of men in front of them (so one of them can see 2 hats, one sees 1 hat and one sees no hats).

After the blindfolds any man may shout out the color of his own hat. But if he is wrong they are all killed. If he is right they are all released.

They have 10 seconds for someone to respond or they are all killed.

What strategy can be used to garauntee they are released?

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Besides simply saying who, it's important to detail how (as there are only 4 choices as to who) the strategy works out.

Oh, because if it were the fourth guy who could see two white hats in front of him, he'd say so immediately, because he doesn't, bloke 3 knows his hat isn't the same as bloke 2's. It's the silence that gives bloke 3 the knowledge that his hat is different to the guy in front's.

Oh, because if it were the fourth guy who could see two white hats in front of him, he'd say so immediately, because he doesn't, bloke 3 knows his hat isn't the same as bloke 2's. It's the silence that gives bloke 3 the knowledge that his hat is different to the guy in front's.

Damn, you edited your post. I missed it.

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No harm no foul... but to keep this from being "pugs personal brain teaser" post if you know this one, just say so until others get a chance ;)

100 pirates are captured by a clan of ninjas. The ninjas tell the pirates that being honrable they will give the pirates a way to be let free, they will be blindfolded and a hat put on their heads (white or black - there are infinite white and black hats to draw from). They will then be lined up on a hill facing down the hill such that each pirate can see every pirate and hat in front of him and blindfolds removed.

Then starting from the back of the line, the last pirate will be asked his hat color. Every pirate can hear what every pirate before him says.

They will progress up the line until all 100 pirates have answered from back to front what their hat color is. If more than 1 gets his wrong, they are all killed. If 1 or 0 gets his wrong, they are all let go.

The pirates are given a day to plan a strategy for this situation.

What strategy will get them released?

Assume smart pirates, math skills and other cognotive skills sufficient to carry out a complex strategy. These are harvard pirates.

There is to be no information traded between pirates after blindfolds are put on - ie they cannot cough, shout or answer in a strange accent to give info, essentially this is a logic solution, not a funny business solution

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After many assumptions the only thing I can figure out, and it is visible if you look carefully, is that they are not both perfect 30/60/90 triangles. If they were, they would both have 32.5 square units of some measure, but, when the subordinate colored parts are calculated they each only come up with 32 square units, again assuming that the triangle parts are 30/60/90. The top drawing is larger than the bottom one, clearly visible when looked at closely, so, the math does not apply. The top triangle is one square unit larger than the bottom one. Good diversion. -

Ok so here is a nerdy one for you...

These two triangles are made out of the same parts, just moved around, but the bottom one is missing a square of coverage... how did this happen?

post-3411-1172010006_thumb.jpg

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