Gadgeguy2009 Posted June 30, 2009 Report Posted June 30, 2009 Hello all, could please someone point me in the right direction (or explain)?
jfreeman420 Posted June 30, 2009 Report Posted June 30, 2009 Go in that direction and make a left...............
trailboss Posted June 30, 2009 Report Posted June 30, 2009 The right direction for freaking what exactly? Col.
wheaton26 Posted June 30, 2009 Report Posted June 30, 2009 Hello all, could please someone point me in the right direction (or explain)? this guy is giving canadians a very bad name.
Mardo Posted June 30, 2009 Report Posted June 30, 2009 LOL! Turn the oven on 350 and bake for 25-30 minutes or until golden brown.
maxman Posted June 30, 2009 Report Posted June 30, 2009 Put the lime In the coconut and shake It all up. (ps) Call me In the morning
specialvat Posted June 30, 2009 Report Posted June 30, 2009 ................Love, oh baby dont hurt me dont hurt me no more. Name that tune perhaps ?
dbutlerman Posted June 30, 2009 Report Posted June 30, 2009 Right: being or located on or directed toward the side of the body to the east when facing north... Direction: The spatial relation between something and the course along which it points or move... This should "Explain" the "Right Direction"
Guest asim Posted June 30, 2009 Report Posted June 30, 2009 i just had some waffles with maple syrup, they were real good..
arty909 Posted June 30, 2009 Report Posted June 30, 2009 Something funky happened when you posted that- Is this the rest of it? Hello all, could please someone point me in the right direction (or explain)? I really like the black steel breitling reps. However I am not exactly sure what black steel is. If it is PVD, than no thank you. I have an expensive gen PVD watch, and only after a short time there are a couple of nicks on it, where the steel shines through. That drives my crazy, as I really anal about my watches. (A nick on a SS watch is much less visible, and therefore disturbs me way less). Is black steel PVD? Or is it the same material deeper down too? Which model / vendor would have a guaranteed Breitling black steel ? Thank you for your advice!
Nanuq Posted June 30, 2009 Report Posted June 30, 2009 Okay, I'll explain it again. But just this once more. Please listen carefully this time. A topological group is locally compact if and only if the identity e of the group has a compact neighborhood. This means that there is some open set V containing e whose closure is compact in the topology of G. A locally compact group G carries an essentially unique natural measure, the Haar measure, which allows one to consistently measure the "size" of sufficiently regular subsets of G. "Sufficiently regular subset" here means a Borel set; that is, an element of the σ-algebra generated by the compact sets. More precisely, a right Haar measure on a locally compact group G is a countably additive measure μ defined on the Borel sets of G which is right invariant in the sense that μ(A x) = μ(A) for x an element of G and A is a Borel subset of G and also satisfies some regularity conditions (spelled out in detail in the Haar measure definition). The take-home concept is, except for positive scale factors, Haar measures are unique. Now then do we need to go over this again?
Guest asim Posted June 30, 2009 Report Posted June 30, 2009 Okay, I'll explain it again. But just this once more. Please listen carefully this time. A topological group is locally compact if and only if the identity e of the group has a compact neighborhood. This means that there is some open set V containing e whose closure is compact in the topology of G. A locally compact group G carries an essentially unique natural measure, the Haar measure, which allows one to consistently measure the "size" of sufficiently regular subsets of G. "Sufficiently regular subset" here means a Borel set; that is, an element of the σ-algebra generated by the compact sets. More precisely, a right Haar measure on a locally compact group G is a countably additive measure μ defined on the Borel sets of G which is right invariant in the sense that μ(A x) = μ(A) for x an element of G and A is a Borel subset of G and also satisfies some regularity conditions (spelled out in detail in the Haar measure definition). The take-home concept is, except for positive scale factors, Haar measures are unique. Now then do we need to go over this again? no no, explain that again
Nanuq Posted June 30, 2009 Report Posted June 30, 2009 Well I left out some of it, hoping that he'd be able to connect the dots. *dripping sarcasm* What I meant to imply was a probabilistic proof of the Weyl integration formula on the unitary group. This relies on a suitable definition of Haar measures conditioned to the existence of a stable subspace with any given dimension. The developed method leads to the following: for this conditional measure, writing $Z_U^{(p)}$ for the first non-zero derivative of the characteristic polynomial at 1, $Z_U^{(p)}$ can be decomposed as an explicit product of $n-p$ independent random variables. This implies a central limit theorem for $\log Z_U^{(p)}$ and asymptotics for the density of $Z_U^{(p)}$ near 0. I mean, duh. Similar limit theorems apply for the orthogonal and symplectic groups. Now if you are mapping x->Ux, Let {ei, e2s ... en} be the complete orthonormal system of Rn, so that if xn = <x, en >=
Nanuq Posted June 30, 2009 Report Posted June 30, 2009 Of course this is assuming 2+2=5 (for very large values of 2)
tomhorn Posted July 1, 2009 Report Posted July 1, 2009 From Two and a Half Men ... Charlie: (trying to explain to Jake, why he had to go out with a divorced woman who gave him her number, even though he promised he wouldn't) Ok, ok...let's say you're a hunter! If a deer takes your gun, shoots itself, then straps itself to the roof of your car...you have to take it home and eat it! Jake: What?!? Charlie: I'm sorry...i can't make it any clearer!
hackR Posted July 1, 2009 Report Posted July 1, 2009 directions: take your right hand and reach behind your back...locate your [censored] and take wallet out of pocket... repeat process until you understand the RWG concept...
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