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Brain Teaser Game!


cornerstone

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Suppose there are 2 red-eyed monks on the island and

you're one of them. Before the visitor arrives you always assume that the

red-eyed monk you observe is the only monk with red eyes -- ie, you're

safe. (That monk is of course thinking the same thing about you.) When

the visitor announces that there are red eyes on the island you expect

the *one* (so you think) red-eyed monk to commit suicide. When they

don't, you realize you're in trouble. They must have been watching

someone else and waiting for that person to commit suicide. The only

person that they could have been watching is you -- you can see that

everyone else on the island has brown eyes so that rules them out. So

because the other red-eyed monk didn't kill himrself on day 1, you deduce

on day 2 that your eyes are red and you kill yourself. The other monk

went through identical reasoning watching you and so will also commit

suicide on day 2.

Supposing there are 3 red-eyed monks, each is watching the other 2 and

expecting, by the reasoning above, that they will both die on day 2. When

they don't, he concludes that they must not be watching just each

other. Since it's symmetric, the other 2 monks are each watching you and

the other one and thinking the same thing. Hence, you all 3 know to kill

yourselves by the 3rd day. etc...

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Suppose there are 2 red-eyed monks on the island and

you're one of them. Before the visitor arrives you always assume that the

red-eyed monk you observe is the only monk with red eyes -- ie, you're

safe. (That monk is of course thinking the same thing about you.) When

the visitor announces that there are red eyes on the island you expect

the *one* (so you think) red-eyed monk to commit suicide. When they

don't, you realize you're in trouble. They must have been watching

someone else and waiting for that person to commit suicide. The only

person that they could have been watching is you -- you can see that

everyone else on the island has brown eyes so that rules them out. So

because the other red-eyed monk didn't kill himrself on day 1, you deduce

on day 2 that your eyes are red and you kill yourself. The other monk

went through identical reasoning watching you and so will also commit

suicide on day 2.

Supposing there are 3 red-eyed monks, each is watching the other 2 and

expecting, by the reasoning above, that they will both die on day 2. When

they don't, he concludes that they must not be watching just each

other. Since it's symmetric, the other 2 monks are each watching you and

the other one and thinking the same thing. Hence, you all 3 know to kill

yourselves by the 3rd day. etc...

RESPECT Edge !!! :thumbsupsmileyanim::thumbsupsmileyanim::thumbsupsmileyanim:

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Suppose there are 2 red-eyed monks on the island and

you're one of them. Before the visitor arrives you always assume that the

red-eyed monk you observe is the only monk with red eyes -- ie, you're

safe. (That monk is of course thinking the same thing about you.) When

the visitor announces that there are red eyes on the island you expect

the *one* (so you think) red-eyed monk to commit suicide. When they

don't, you realize you're in trouble. They must have been watching

someone else and waiting for that person to commit suicide. The only

person that they could have been watching is you -- you can see that

everyone else on the island has brown eyes so that rules them out. So

because the other red-eyed monk didn't kill himrself on day 1, you deduce

on day 2 that your eyes are red and you kill yourself. The other monk

went through identical reasoning watching you and so will also commit

suicide on day 2.

Supposing there are 3 red-eyed monks, each is watching the other 2 and

expecting, by the reasoning above, that they will both die on day 2. When

they don't, he concludes that they must not be watching just each

other. Since it's symmetric, the other 2 monks are each watching you and

the other one and thinking the same thing. Hence, you all 3 know to kill

yourselves by the 3rd day. etc...

WINNER :3a:

What happens to the brown eyes monks?

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You walk into a room in which there are three primates: a chimpanzee, an orangutan, and a gorilla. The chimpanzee is holding a banana in each hand, the orangutan is holding a big stick, and the gorilla is holding nothing. Which primate in the room is the smartest?

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